Define CRS in process api request in python

Hello Sentinel-hub team,

I am trying to get tiff format sentinel-2 images using the process API and I am not sure how to define the CRS:3035, is there an option to do that in the following piece of code.

bbox = BBox(bbox=[6.80668698, 51.61359378,  6.8452312 , 51.6375781], crs=....)

request = SentinelHubRequest(
    evalscript=evalscript_cloud_mosaick,
    input_data=[
        SentinelHubRequest.input_data(
            data_collection=DataCollection.SENTINEL2_L2A,          
            time_interval=('2020-10-14', '2020-11-14'),
    
        ),
    ],
    responses=[
        SentinelHubRequest.output_response('default',MimeType.TIFF),
    ],
    bbox=bbox,
    size=[512, 343.697],
    config=config
)

response = request.get_data()```

Is this what you’re after?

from sentinelhub import CRS
crs_3035 = CRS(3035)

Yes, can I define this in the bbox?

you can indeed, this should work:

BBox(bbox=[6.80668698, 51.61359378,  6.8452312 , 51.6375781], crs=CRS(3035))

Thanks Ziga, I just tried it. It works, thanks for the quick response!

Excellent! Always happy to help

1 Like